You have 11.27 moles of Cl2 gas. How many moles of NaBr do you need to completely undergo this reaction?

22.54 moles of NaBr are needed

Explanation:

The reaction of Cl2 with NaBr occurs as follows:

Cl2 + 2NaBr → 2NaCl + Br2

Where 1 mole of Cl2 requires 2 moles of NaBr for a complete reaction

As in the problem, we have 11.27 moles of Cl2, the moles of NaBr required are:

11.27mol Cl2 * (2mol NaBr / 1mol Br2) =

the product of the pressure and volume is also constant

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