PLEASE PLEASE HELP What is the pOH of a solution with an OH- ion concentration of

6.0E-4?

3.22

Explanation:

The pOH is defined as:

pOH = - log [OH⁻]

From the problem, we have [OH⁻] = 6.0 x 10⁻⁴.

Thus, we introduce the concentration in the equation to calculate the pOH:

pOH = - log [OH⁻] = -log (6.0 x 10⁻⁴) = 3.22

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explanation:

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