44.0L of O2 react with excess Sulfur dioxide gas. All gases are kept at the same temperature, pressure, and volume. What will be the theoretical yield of Sulfur trioxide gas in Liters?

The theoretical yield of sulfur trioxide is 88.0 Litres

Explanation:

The chemical reaction occurring between oxygen and sulfur dioxide is given in the chemical equation below :

2SO₂ + O₂ > 2SO₃

From the equation of reaction, 2 moles of sulfur dioxide reacts with 1 mole of oxygen to produce 2 moles of sulfur trioxide.

Volume of 1 mole of a gas at STP is 22.4 L

Number of moles of gas in 44.0 L = 44.0/22.4 moles

1 mole of oxygen reacts with 2 moles sulfur dioxide to produce 2 moles of sulfur trioxide;

44/22.4 moles of oxygen will react with excess sulfur dioxide to produce 2 × 44/22.4 moles of sulfur trioxide = 88/22.4 moles of sulfur trioxide

88/22.4 moles of sulfur trioxide will have a volume of 88/22.4 × 22.4 Litres = 88.0 Litres

Therefore, the theoretical yield of sulfur trioxide is 88.0 Litres

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'