El metal Mg reacciona con el Hcl para producir gas Hidrógeno Mg +2HCl---MgCl2 + H2. ¿Qué volumen en Litros de H2 en condiciones STP se liberan cuando reaccionan 8.25g de Mg? * 8.60L 6.60L 7.60L 16.60L

7.60 L of hydrogen gas will be liberated.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

   ......(1)

Given mass of Mg = 8.25 g

Molar mass of Mg = 24.305 g/mol

Plugging values in equation 1:

The given chemical equation follows:

By the stoichiometry of reaction:

If 1 mole of magnesium produces 1 mole of hydrogen gas

So, 0.340 moles of magnesium will be produce = of hydrogen gas

At STP conditions:

1 mole of a gas occupies 22.4 L of volume

So, 0.340 moles of hydrogen gas will occupy = of hydrogen gas

Hence, 7.60 L of hydrogen gas will be liberated.

not clear