What is the molarity of an aqueous solution containing 1.5 moles of calcium chloride in 2.75 L of solution? A. 0.004 M B. 0.55 M C. 1.83 M D. 4.13 M

B. 0.55 M

Explanation:

Step 1: Given data

Moles of calcium chloride (solute): 1.5 molVolume of solution: 2.75 M

Step 2: Calculate the molarity of the aqueous solution

The molarity is a way to express the concentration of a solution. It is equal to the quotient between the moles of solute and the liters of solution.

M = moles of solute / liters of solution

M = 1.5 mol / 2.75 L = 0.55 mol/L = 0.55 M

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.

D-no effect on the rate