The gas left in a hairspray can is at a pressure of 121.2kPa at 25.0°C. If this can is thrown into a fire, what will be the resulting pressure if the fire reaches 2,111°C

969.6 kPa

Explanation:

Applying,

P/T = P'/T' Equation 1

Where P = Initial pressure of the gas, T = Initial temperature of the gas, P' = Final pressure of the gas, T' = Final temperature of the gas

make P' the subject of the equation

P' = PT'/T Equation 2

From the question,

Given: P = 121.2 kPa, T' = 2111°C = (273+2111) = 2384 K, T = 25°C = (273+25) K = 298 K

Substitute these values into equation 2

P' = (121.2×2384)298

P' = 969.6 kPa

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3