Please help me anyone

The answer to your question is given below

Explanation:

To prepare 3 M solution of NaOH, do the following:

1. Determine the number of mole of NaOH in the solution. This can be obtained as follow:

Molarity of NaOH = 3 M

Volume = 1 L

Mole of NaOH =?

Mole = Molarity × Volume

Mole of NaOH = 3 × 1

Mole of NaOH = 3 moles

2. Determine the mass of 3 moles of NaOH. This can be obtained as follow:

Mole of NaOH = 3 moles

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mass of NaOH =?

Mass = Mole × molar mass

Mass of NaOH = 3 × 40

Mass of NaOH = 120 g

3. Measure 120 g of NaOH and dissolve in 1 L of water in a volumetric flask to produce 3 M of the solution.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm