How many grams of glucose, C6H12O6, do you need to make a 50 mL solution that has a concentration of 2.0 M? PLEASE HELP ASAP

18.0g of glucose are needed

Explanation:

Molarity, M, is an unit of concentration widely used in chemistry. Is defined as the ratio between moles of solute (In this case, glucose) and liters of solution (50mL = 0.050L).

To solve this question we must find the moles of glucose that we need to prepare the solution. Then, using the molar mass of glucose (180.156g/mol) we can find the mass that we need:

Moles Glucose:

0.050L * (2.0mol / L) = 0.100 moles Glucose

Mass glucose:

0.100moles Glucose * (180.156g / mol) = 18.0g of glucose are needed

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

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