How many grams of glucose, C6H12O6, do you need to make a 50 mL solution that has a concentration of 2.0 M?

18g

Explanation:

Molarity = n/V

Where;

n = number of moles (mol)

V = volume (L)

Based on the given information,

M = 2.0 M

V = 50 mL = 50/1000 = 0.05L

Using; Molarity = n/V

n = molarity × volume

n = 2.0 × 0.05

n = 0.1mol

Using mole = mass/molar mass

Molar mass of C6H12O6 = 12(6) + 1(12) + 16(6)

= 72 + 12 + 96

= 180g/mol

Mass = mole × molar mass

Mass = 0.1 × 180

Mass = 18g

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2