What is the molarity when 25.0 g of the compound NaClO3 is placed in 85.0 mL of solution?

Molarity when 25.0 g of the compound is placed in 85.0 mL of solution is 294.12 M.

Explanation:

Given: Mass = 25.0 g

Volume  = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity is the number of moles of a substance divided by volume in liter.

Hence, molarity of given solution is calculated as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that molarity when 25.0 g of the compound is placed in 85.0 mL of solution is 294.12 M.

dynamic equilibrium is the answer.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)