A student has 475 mL of a 4.5 M HNO3 solution. He leaves the top of the container Monday morning the volume of solution is now 347 mL. What is the conventtration of the solution now

6.1 M

Explanation:

Step 1: Calculate the moles of HNO₃ in the initial solution

A student has 475 mL (0.475 L) of a 4.5 M HNO₃ (4.5 mol HNO₃/ L) solution.

0.475 L × 4.5 mol HNO₃/ L = 2.1 mol HNO₃

He leaves the top of the container open, so water will evaporate, but the moles of HNO₃ will remain the same.

Step 2: Calculate the final concentration of the solution

2.1 moles of HNO₃ are in 347 mL (0.347 L) of solution.

[HNO₃] = 2.1 mol / 0.347 L = 6.1 M

the formula would be mgso4

mgso[subscript]4

increased stability in the completion of fluorine's outer shell.