A car starts out when the air temperature is 298 K and the absolute (total) air pressure in the tires is 500 kPa. After driving a while, the temperature of the air in the tires increases to 315 K. What is the pressure in the tires at that point, assuming their volume does not change

The pressure in the tires at that point is 528.52 kPa.

Explanation:

Given: = 500 K,           = 500 kPa

= 315 K,               = ?

According to Gay-Lussac's law, at constant volume the pressure of a gas is directly proportional to temperature.

Formula used to calculate the pressure is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the pressure in the tires at that point is 528.52 kPa.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles