5. Suppose you add 2.0 mL of 0.10 M HCl to 100 ml of buffer having 0.10 M HA and 0.20 M NaA. The pKa of the acid HA is 4.82. a. Which species will react strongly with one another

The HCl react strongly with NaA

Explanation:

The buffer is an aqueous mixture of a weak acid and its conjugate base, or vice versa.

In the problem, you have the weak acid, HA, in a mixture with the conjugate base, NaA. A strong acif as HCl is added. The acids react with bases, the only base present is NaA, that means:

The HCl react strongly with NaA

The reaction is:

HCl + NaA → NaCl + HA

solute : a solute is a substance that is dissolved in another substance is known as a solvent. it is mixed with a special mixture know as homogeneous mixture.

solvent: a solvent is a substance that dissolved a solute, which results in a solution is known as solvent.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2