The gas in a balloon occupies 1.25 L at 298 K. At what temperature in Celsius (C) will the balloon expand to 6.50 L? (Remember to keep the correct place value in your final answer- thousands place)

1549.6K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information supplied in this question:

V1 = 1.25 L

V2 = 6.50 L

T1 = 298K

T2 = ?

Using V1/T1 = V2/T2

1.25/298 = 6.5/T2

0.004195 = 6.5/T2

T2 = 6.5 ÷ 0.004195

T2 = 1549.6K

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