3. When Sato rents a venue for prom, they usually get access to it the day of in order to decorate. This year, they get access around noon to start. The "balloon manager" knows
that as the day proceeds, the temperature will naturally drop and the balloons will
deflate because of this. To compensate for this, this kid plans to put extra air in the
balloons so that even when they deflate because of the falling temperature, they will still
look good. If the balloons need 1.5L of helium gas to stay looking good, and the
temperature that night is going to be 58°F, to what volume should the balloon manager
fill the balloons at midday when the temperature is 76°F?

The correct answer is weight.

Ibelieve it is b. proton.hope my answer has you : )

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters