A 1.50 L sample of neon gas at 1.10 atm and 25 °C is heated to 45 °C. The neon gas is then subjected to a pressure of 1.50 atm. Determine the new volume of the neon gas

1.17 L

Explanation:

Step 1: Given data

Step 2: Convert the temperatures to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 25°C + 273.15 = 298 K

K = 45°C + 273.15 = 318 K

Step 3: Calculate the final volume of the neon gas

If we assume ideal behavior, we can calculate the final volume of the neon gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.10 atm × 1.50 L × 318 K / 298 K × 1.50 atm = 1.17 L

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: