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Chemistry, 24.05.2021 05:10 xaviercamara080
Im brain dead please help me
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Chemistry, 22.06.2019 16:50, TrueKing184
Answer asap need by wednesday morning explain how a buffer works, using an ethanoic acid/sodium ethanoate system including how the system resists changes in ph upon addition of a small amount of base and upon addition of a small amount of acid respectively. include the following calculations in your i. calculate the ph of a solution made by mixing 25cm3 0.1m ch3cooh and 40cm3 0.1m ch3coo-na+. [ka = 1.74 x 10-5 m] ii. calculate the ph following the addition of a 10cm3 portion of 0.08 m naoh to 500cm3 of this buffer solution. iii. calculate the ph following the addition of a 10cm3 portion of 0.08 m hcl to 200cm3 of the original buffer solution.
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Chemistry, 23.06.2019 15:40, bignutz29
The poh of a solution is 6.0. which statement is correct? use poh=-log[oh and ph+poh= 14 o o o the ph of the solution is 20.0. the concentration of oh ions is 1.0 x 10-8 m- the concentration of oh ions is 1.0 x 106 m- the ph of the solution is 8.0.
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