What is the equilibrium constant for the chemical equation: Mg3P2 (s) ↔ 3Mg+2 (aq) + 2P-3 (aq)

At equilibrium, the concentration of Mg3P2 is 5.5 x 10-6 M, the concentration of magnesium ions is 7.2 x 10-5 M, and the concentration of phosphide ions is 9.8 x 10-8 M.
Show your work.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g