Question 26 (3 points) In the lab, a cube of wood has a mass of 41.2 grams and its temperature rises from
28.1°C to 65.1°C when placed outside in the sun for a period of time. Calculate the
amount of heat absorbed by the wood. The specific heat of wood is 1.76 J/g°C.
6
Round your answer to 1 decimal place.
Your
1
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Question 27 (3 points)

2682.9J is the heat absorbed by the wood

Explanation:

To find the heat absorbed for a material we must use the equation:

Q = S*m*ΔT

Where Q is heat absorbed in Joules

S is specific heat of the material = 1.76J/g°C for wood

m is the mass of the material = 41.2g

ΔT is change in temperature = 65.1°C - 28.1°C = 37.0°C

Replacing:

Q = 1.76J/g°C*41.2g*37.0°C

Q = 2682.9J is the heat absorbed by the wood

here are some of the ways in which chemical and nuclear reactions differ.

explanation:

the correct answer would be b) volume versus temperature, because they are also directly proportional.