Find the zeros of the quadratic equation f(x)= 6x²-3, and verify the relation between its zeros and coefficients. using the formula
alpha+beta= -b/a
alpha × beta = c/a​

Step-by-step explanation:

We are already given the following formulas :-

Given that the polynomial is :-

Now, we will use factorisation as our first weapon :-

6x² -3 = 0 [As we have to find the zeroes of the equation]

6x² = 3

x² = 

x² = 

x = 

Now, we can take one zero as 1/Root 2 and other -1/root 2

0 |0 Hence verified.

Hence, proved.

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