If you want to make 8.00 moles of AlF₃ how many moles of F₂ will you need, using the following balanced chemical equation? 2 Al + 3 F₂ → 2 AlF₃

You will need 12.0 moles of F₂

Explanation:

Based on the chemical equation, 2 moles of AlF₃ are produced when 3 moles of F₂ are added in an excess of Al.

Using this expression: 2mol AlF₃ = 3mol F₂ we can find the moles of F₂ as follows:

8.00 mol AlF₃ * (3mol F₂ / 2mol AlF₃) =

You will need 12.0 moles of F₂

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic