When 3.0 liters of propane (C3H8) gas is completely combusted to form water vapor and carbon dioxide at STP what mass of water vapor will result? C3H8 (g) + 5 O2 (g) = 3CO2 (g) + 4H2O (g)

Correct option is

D

72.0g

The molar masses of propane and water are 44 g/mol and 18 g/mol respectively.

44.0 grams of propane corresponds to 1 mole of propane.

According to the balance chemical equation, C

3

H

8

(g)+5O

2

(g)→3CO

2

(g)+4H

2

O(l),

1 mole of propane gives 4 moles of water.

Thus, the combustion of 44.0 g (1 mole) of propane will give 4 moles of water.

Mass of water obtained =4×18=72.0 g.

Hence, option D is correct.

the dependant variable is spilled water

the independent is the heat