How many degrees would the temperature of a 45.0 g piece of iron increase if 7,680 J of energy are applied to it? (The specific heat of iron is 0.449 J/g°C) Question 10 options:

76.6°C

155,000°C

380°C

0.0130°C

Hi + naoh -> h2o + nal

Answer:             1.0  × 10⁻⁵ msolution:                     as we know ph is given as,                                    ph  = -log [h⁺]and,                                    [h⁺]  =  10^-ph    (1)putting value of ph in eq. 1,                                    [h⁺]  =  10⁻⁵                                    [h⁺]  =  1.0  × 10⁻⁵ m

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Answercalcium