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Instructions

Balance each equation. Be sure to show off your lists! Remember you cannot add or place off coefficients in the middle of a chemical formula.

Example

2Na + MgF2 —-> 2NaF + 2Mg
Na= 2. Na=2
Mg= 1. Mg=1
F= 2. F=2

3. Cl₂ + 2KI --> 2KCl + I₂

Cl = 2        Cl = 2

K = 2         K = 2

I = 2           I = 2

4. 2NaCl --> 2Na + Cl₂

Na = 2      Na = 2

Cl = 2       Cl = 2

5. 4Na + O₂ --> 2Na₂O

Na = 4      Na = 4

O = 2        O = 2

6. 2Na + 2HCl --> H₂ + 2NaCl

Na = 2         Na = 2

H = 2           H = 2

Cl = 2          Cl = 2

7. 2K + Cl₂ --> 2KCl

K = 2         K = 2

Cl = 2        Cl = 2

answer: lol

explanation:

lol

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.