A gas has a pressure of 0.370 atm at 30,0 °C. What is the pressure at standard temperature? (assume constant volume)

0.333 atm

Explanation:

Step 1: Given data

Step 2: Convert 30.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 30.0 + 273.15 = 303.2 K

Step 3: Calculate the final pressure of the gas

If we assume ideal behavior and constant volume, we can calculate the final pressure od the gas using Gay-Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 0.370 atm × 273.15 K/303.2 K = 0.333 atm

- "the choice that is not an indicator of a chemical change is "state of matter changes". more common than not, chemical reactions produce energy in the form of light or heat. along with energy, they also produce a new substance called the product that could be in any state of matter (solid, gas, or liquid)."