13. Given the equation: CH4 + 2 O2 → CO2+ 2 H2O

How many grams of carbon dioxide (CO2) are produced from the combustion of 26.00 g of CH4?

Your

14. Given the equation:

Cl2 + 2KBr → Br2 + 2KCl

How many grams of potassium chloride (KCl) can be produced from 2.00 g of potassium
bromide (KBr)?

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;