If 5.0 liters of hydrogen react with excess oxygen, what mass of water would be produced?

our equation specifies that

32

⋅

g

of dioxygen and

4

⋅

g

of dihydrogen give

36

⋅

g

of water upon reaction, so

Explanation:

2

H

2

(

g

)

+

O

2

(

g

)

→

2

H

2

O

(

g

)

We started with

5.0

⋅

g

32.00

⋅

g

⋅

m

o

l

−

1

=

0.156

⋅

m

o

l

dioxygen

.

Given excess dihydrogen, this molar quantity thus gives

2

×

0.156

⋅

m

o

l

water.

And thus,

2

×

0.156

⋅

m

o

l

×

18.01

⋅

g

⋅

m

o

l

−

1

≅

6

⋅

g

water are evolved. Is this reaction exothermic or endothermic?

so what is the problem with your lab report and whats the subject of the lab report? i will you