Linda performed the following trials in an experiment. Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0 °C.
Trial 2: Heat 40.0 grams of water at 30.0 °C to a final temperature of 40.0 °C.
Which statement is true about the experiments? (5 points)
The heat absorbed in Trial 1 is about 1,674 ) greater than the heat absorbed in Trial 2.
O The heat absorbed in Trial 1 is about 3,347) greater than the heat absorbed in Trial 2
O The same amount of heat is absorbed in both the experiments because the heat absorbed depends only on the final temperature,
The same amount of heat is absorbed in both the experiments because the product of mass, specific heat capacity, and change in temperature are the
same.

O The heat absorbed in Trial 1 is about 3,347) greater than the heat absorbed in Trial 2

Explanation:

Using the formula as follows;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat of water = 4.18J/g°C

∆T = change in temperature (°C)

* For trial 1:

m = 30g

∆T = 40°C - 0°C = 40°C

Q = 30 × 4.18 × 40

Q = 5016J

* For trial 2:

m = 40g

∆T = 40°C - 30°C = 10°C

Q = 40 × 4.18 × 10

Q = 1672J

From the above results, it is clear that the amount of heat absorbed in trial 1 (5016J) is greater than that absorbed in trial 2(1672J) with a difference of 3344.

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