Use the ΔH°f information provided to calculate ΔH°rxn for the following reaction: SO2Cl2 (g) + 2H2O(l) → 2HCl(g) + H2SO4(l) ΔH°rxn = ?

Δ∘ = ΣΔ∘() − ΣΔ∘()

ΔH°f (kJ/mol)

SO2Cl2(g) -364

H2O(l) -286

HCl(g) -92

H2SO4(l) -814

-422 kJ

-62 kJ

+161 kJ

-256 kJ

+800 kJ

the volume increases

can you attach the

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol