What is the cncentration of 75mL solution of HCl, if the solution neutralizes after 17.89 mL of 1M NaOH is added to the solution.

0.24 M

Explanation:

Step 1: Write the balanced neutralization reaction

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of NaOH

17.89 mL (0.01789 L) of 1 M NaOH react.

0.01789 L × 1 mol/L = 0.01789 mol

Step 3: Calculate the moles of HCl that reacted with 0.01789 moles of NaOH

The molar ratio of NaOH to HCl is 1:1. The moles of HCl that reacted are 1/1 × 0.01789 mol = 0.01789 mol.

Step 4: Calculate the molar concentration of HCl

0.01789 moles are in 75 mL (0.075 L) of HCl,

[HCl] = 0.01789 mol/0.075 L = 0.24 M