What is the new concentration of a solution after 250mL of 2.5M sulfuric acid is diluted to a final volume of 700mL? Please show your work

The new concentration of the solution is 0.89 M.

Explanation:

In chemistry, dilution is the reduction in concentration of a chemical in a solution. This is accomplished by adding more solvent to the same amount of solute.

So, in a dilution, the amount of solute does not vary, but the volume of the solvent varies: as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

In this case:

Replacing:

2.5 M* 250 mL= Cf* 700 mL

Solving:

Cf= 0.89 M

The new concentration of the solution is 0.89 M.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.