What is the molality of an acetic acid solution that contains 0.500 mol of HC2H3O2 (molar mass: 60g/mol) in 0.800 kg of water?

The molality of given acetic acid solution is 0.625 m.

Explanation:

Given: Moles of solute = 0.5 mol

Mass of solvent = 0.8 kg

Molality is the number of moles of solute present in a kg of solvent.

Therefore, molality of the given solution is calculated as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the molality of given acetic acid solution is 0.625 m.

the answer for sodium is 0.186

the answer for rubidium is 0.251

the answer is option a.