Aluminum reacts with Oxygen gas to form Aluminum Oxide: 4 Al + 3 O2 --> 2 Al2O3. If you are given 176.9 grams of aluminum how many moles of oxygen would you need to react all of the aluminum? A.1.640 mol O2
B. 4.917 mol O2
C. 3.278 mol O2
D. 6.556 mol O2
E. 19.70 mol O2
F. None of the above

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole