-gas noble sin electrones en los orbitales p -Un elemento que tenga 2 electrones de valencia con los números cuánticos: n= 4,
l =0 y 8 electrones n=3, l = 2
-Dos elementos con 2 electrones 3p desapareados.
-Un elemento con un orbital d lleno y un s semilleno.

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.