What volume of solution would be needed to deliver 3.0 mg of a drug if the concentration of the drug in the solution was 3.5% (m/v)? Show work please

The correct answer is "85.71 mg".

Explanation:

The given values are:

Mass of drug,

= 3.0 mg

Mass percentage,

= 3.5%

As we know,

⇒  

Or,

⇒  

On substituting the values, we get

⇒                              

⇒                              

⇒                              

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

answerca air mass;