2. How many moles of oxygen are produced by the decomposition of 6 moles of KCIO3? _KCIO3 -> _KCI+_02
3. How many moles of Hy are produced from the reaction of three moles of Zn?
_Zn + _HCI -> _ZnCl2 + _H2
Mass-Mass Conversions
4. How many grams of potassium chloride are produced if 25g of potassium chlorate decompose?
__KCIO3 -> _KCI + _02
5. How many grams of hydrogen are necessary to react completely with 50.0g of nitrogen?
_N2 + H2 -> NH3
6. How many grams of copper (II) sulfate are needed to produce 88g of sodium sulfate?
_NaOH + _CuSO4 ->_Na2SO4 + _Cu(OH)2
Mass-Mol Conversions
7. How many mol of sodium sulfate are needed to produce 23.9g of copper (11) hydroxide?
_NaOH + _CuSO4 -> _Na2SO4 + _Cu(OH)2
8. How many mol of zinc chloride are produced from 26,4g of HCI?
_Zn + _HCI -> _ZnCl2 + _H2
Mol-Mass Conversions
9. How many grams of potassium chlorate are needed to produce 3 mol of oxygen?
_KCIO, -> __KCI+ _02
10. How many grams of sodium sulfate are produced from 0.77 mol of sodium hydroxide?
NaOH + __CuSO4 --> __Na2SO4 + _Cu(OH)2
Look

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

the answer for sodium is 0.186

the answer for rubidium is 0.251