The equilibrium constant, Kp, for the following reaction is 1.3x1014 at 850°c. C(s)+CO2(g)= 2 CO(g)
a)Calculate the equilibrium constant, kp, for the reaction below at 850°c.
2 C(s)+2 CO2(g)= 4 CO(g)
b)Calculate the equilibrium constant, kp, for the reaction below at 850°c.
2 CO(g)= C(s)+CO2(g)
c)If the equilibrium constant, kp, is 167 for COCl2(g)= CO(g)+ Cl2(g) at 850°c, find kp for COCl2(g)=Cl2(g)+1/2 C(s) at 850°c.
Answers: 3
Chemistry, 21.06.2019 20:30, mayamabjishovrvq9
1. calculate the approximate enthalpy of the reaction in joules. estimate that 1.0 ml of vinegar has the same thermal mass as 1.0 ml of water. iqnore the thermal mass of th sodium bicarbonate. note: it takes about 4.2 joules () to change 1.0 gram (1.0ml) of water 1.0 c
Answers: 2
Chemistry, 22.06.2019 05:30, stellaglenn205
What reaction is taking place? 02 + c3h8 = h20 + co2
Answers: 1
Chemistry, 22.06.2019 09:30, matpakootas521
Why do cells appear different in distilled water than they do in 10% salt water?
Answers: 2
The equilibrium constant, Kp, for the following reaction is 1.3x1014 at 850°c. C(s)+CO2(g)= 2 CO(g)...
Social Studies, 21.02.2022 07:50
Mathematics, 21.02.2022 07:50
Mathematics, 21.02.2022 07:50
Biology, 21.02.2022 07:50