Carry out the experiment the way you described it in task 1, part D. Perform three trials for each drop height, and record the data in the table. Estimate heights to the nearest centimeter. (You may choose to reduce the simulation rate and watch the bounces in slow motion to improve your data collection.) Finally, average the bounce height measurements to get a final reading. Round the average bounce heights to the nearest whole number.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

it is stable as it is in group 0 which have full outer shells of electrons