How many L of 3.0M HCl is required to react completely with 750mL of 2.0M Ca(OH)2? PLEASEEE help me solve this stoichiometry question! i need to be able to explain it. will give extra points and brainliest

*tilts head* sounds more like a statement

that tool would be a compass

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally