From the following enthalpy changes,
2PCl3(l) → 2P(s) + 3Cl2(g) ∆H = -640 kJ
2P(s) + 5Cl2(g)...
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Chemistry, 06.05.2021 22:40 emilyscroggins794
From the following enthalpy changes,
2PCl3(l) → 2P(s) + 3Cl2(g) ∆H = -640 kJ
2P(s) + 5Cl2(g) → 2PCl5(s) ∆H = -886 kJ
calculate the value of ∆H for the reaction
PCl3(l) + Cl2(g) → PCl5(s) ∆H = ??
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