Use the following chemical equation for the remaining questions: 2LiBr + I2 → 2LiI + Br2
** answers should be in correct number of significant digits for 2a and 2b**
2a. 174 g LiBr is equal to how many moles of LiBr?
1 mol
1.00 mol
2.00 mol
2 mol

2b. If 812 g LiBr is added to the reaction, how many liters of Br2 will be produced?
22.40 L
52.3 L
52.27 L
22.4 L

Honors Only
2c. If 22 g LiBr produces 41 g LiI and 35 g I2 produces 45 g LiI, which reactant is the limiting reactant?
LiBr
I2
LiI
Br2

i believe the answer is three water molecules

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.