For the oxidation of iron to form iron(iii)oxide 4Fe(s)+3O2(g)=2Fe2O3(s) deltaS^o=-549.73J×K^-1 at 298K
the enthalpy of formation of Fe2O3(s) is -824.2 kj×mol^-1. what is the standard change in gibbs free energy for this reaction at 298K? Delta G^o=delta H^o-T delta S^o

only god knows the answer bby

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.