Use dimensional analysis (unit conversions) and the reaction below to answer the following questions: 2 Al(NO3)3 (aq) + 3 K2SO4 (aq) → Al2(SO4)3 (s) + 6 KNO3 (aq)

How many moles are in 32.7 grams of aluminum nitrate, Al(NO3)3?

How many moles of aluminum sulfate, Al2(SO4)3, could be produced from 32.7 grams of aluminum nitrate, Al(NO3)3?

How many grams of aluminum sulfate, Al2(SO4)3, could be produced from 32.7 grams of aluminum nitrate, Al(NO3)3?

What mass of aluminum nitrate, Al(NO3)3, is needed to produce 500.0 grams of aluminum sulfate, Al2(SO4)3?

What mass of potassium sulfate, K2SO4, is needed to produce 500.0 grams of aluminum sulfate, Al2(SO4)3?

If you ran this reaction using the amounts determined in questions 4 and 5 but only created 460.1 grams of aluminum sulfate, Al2(SO4)3, what would your percent yield be? (Remember: the theoretical yield in this case is 500.0 grams.)