Complex Ion Formation:Cu(NH3)42 Ecell, after adding 6 M NH3to the copper cell 0.77V. Use the Nernst equation to calculate the concentration of that free copper (II) ion that is in equilibrium with the complexed copper (II) ion, Cu(NH3)42 in the solution. Does the calculated value for the [Cu2 ] make sense (look up the Kf for the formation of Cu(NH3)42 ) and rationalize your findings)

i believe it is c.) 1575 j.

може ли да зареждате повече информация, моля

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole