The strength of the solution containing 9 g of glucose (C6H12O6) per 500 cm3 will be A. 0.01 M.
B. 0.1 M.
C. 1.0 M.
D. 1.8 M.

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.

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What do you need with it’s not a question your just stating what it says