The activation energy of an isomerization reaction which obeys 1st-order kinetics is known to be 100 kJ/mol and the pre-exponential of reaction is 1x105 cm/min. When the isomerization reaction is run under strong pore diffusion limitations at 400 K, 400 g of catalyst are required to achieve 60% conversion. a) Write the mole balance for the packed-bed reactor. b) Calculate how much catalyst is required to get 60% conversion if the temperature is raised to 445 K

The answer is letter c

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

Reaction type : double replacement hcl + lioh = h2o + licl