Hydrogen gas reacts with chlorine gas to form hydrogen chloride as shown in the following reaction: H2 (9) + Cl2 (g) + 2HCl (9) If a 454.4 g sample of chlorine gas (MM = 71.0 g/mol) was reacted with excess hydrogen at 565 K and 2.30 atm, how many grams of hydrogen chloride gas (MM = 36.5 g/mol) are produced? g Your answer should be rounded to three significant figures. Do not include units in your answer​

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃. 

  the moles   of   sulfuric acid   that are needed to react   completely with 6.4   moles   of lithium hydroxide   is 12.8   moles ( answer a)

calculation

step 1 : write a balanced   chemical equation

2lioh   + h₂so₄   →   li₂so₄   +2h₂o

step 2 : use the mole ratio   to determine   the   moles h₂so₄

from   equation above   lioh: h₂so₄   is 2: 1 therefore   the moles of h₂so₄

= 6.4   x 2/1   = 12.8   moles   of h₂so₄