Calculate delta G for the following rxn at 25 degrees celcius.
3Mn2+ (aq) + 2Al(s) -><- 3Mn(s) + 2Al3+ (aq)
The
anode= Mn2+ + 2e- -> Mn
= -1.18 V
The
Cathode= Al3+ + 3e- -> Al
= -1.66 V
The Ecell= -1.66-(-1.18)= -0.48 V
But I do not know how to find Delta G.
Delta G= -nFE
The answer is in kj/mol.
Can anyone help?
Answers: 1
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Calculate delta G for the following rxn at 25 degrees celcius.
3Mn2+ (aq) + 2Al(s) -><- 3Mn(...
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