Carbon monoxide and oxygen gas react to form carbon dioxide as shown in the following reaction:
2CO (g) + O2 (g) → 2CO2 (g)
If a 25.0 L sample of carbon monoxide gas was reacted with
excess oxygen at 100 °C and 110. kPa, how many moles of
carbon dioxide is produced?
moles

the answer is   c.) 1575 j.

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml