What pressure will be needed to reduce the volume of 77.4 L of helium at 98.0kPa to a volume of 60.0L?

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the final pressure

98 kPa = 98,000 Pa

We have

We have the final answer as

Hope this helps you

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